71. Simplify Path Medium
You are given an absolute path for a Unix-style file system, which always begins with a slash '/'. Your task is to transform this absolute path into its simplified canonical path.
The rules of a Unix-style file system are as follows:
- A single period
'.'represents the current directory. - A double period
'..'represents the previous/parent directory. - Multiple consecutive slashes such as
'//'and'///'are treated as a single slash'/'. - Any sequence of periods that does not match the rules above should be treated as a valid directory or file name. For example,
'...'and'....'are valid directory or file names.
The simplified canonical path should follow these rules:
- The path must start with a single slash
'/'. - Directories within the path must be separated by exactly one slash
'/'. - The path must not end with a slash
'/', unless it is the root directory. - The path must not have any single or double periods (
'.'and'..') used to denote current or parent directories.
Return the simplified canonical path.
Example 1:
Input: path = "/home/"
Output: "/home"
Explanation: The trailing slash should be removed.
Example 2:
Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: Multiple consecutive slashes are replaced by a single one.
Example 3:
Input: path = "/home/user/Documents/../Pictures"
Output: "/home/user/Pictures"
Explanation: A double period ".." refers to the directory up a level (the parent directory).
Example 4:
Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is not possible.
Example 5:
Input: path = "/.../a/../b/c/../d/./"
Output: "/.../b/d"
Explanation: "..." is a valid name for a directory in this problem.
Approach
Input: A string path
Output: Return a more concise canonical path
This problem belongs to the Basic Stack category.
- We can split the path by
/, and process each segment: - Notice
""or".": Skip (current directory). - Notice
"..": Pop from stack (return to previous level processing. If stack is empty, do nothing). - Normal directory name: Push onto stack.
- Finally use
'/' + '/'.join(stack)to connect into canonical absolute path.
Implementation
class Solution:
def simplifyPath(self, path: str) -> str:
stack = []
for part in path.split('/'):
if part == "" or part == ".": # Empty part or current directory, ignore
continue
if part == "..": # Previous level, pop from stack (if exists)
if stack:
stack.pop()
else: # Normal directory name, push
stack.append(part)
# Root directory is "/"; otherwise join with "/"
return "/" + "/".join(stack)/**
* @param {string} path
* @return {string}
*/
var simplifyPath = function(path) {
const stack = [];
path.split('/').forEach(part => {
if (part === '' || part === '.') return;
if (part === '..') {
if (stack.length) stack.pop();
} else {
stack.push(part);
}
});
return '/' + stack.join('/');
};Complexity Analysis
- Time Complexity:
O(n) - Space Complexity:
O(n)