1732. Find the Highest Altitude Easy
There is a biker going on a road trip. The road trip consists of n + 1 points at different altitudes. The biker starts his trip on point 0 with altitude equal 0.
You are given an integer array gain of length n where gain[i] is the net gain in altitude between points i and i + 1 for all (0 <= i < n). Return the highest altitude of a point.
Example 1:
Input: gain = [-5,1,5,0,-7]
Output: 1
Explanation: The altitudes are [0,-5,-4,1,1,-6]. The highest is 1.
Example 2:
Input: gain = [-4,-3,-2,-1,4,3,2]
Output: 0
Explanation: The altitudes are [0,-4,-7,-9,-10,-6,-3,-1]. The highest is 0.
Approach
Input: An integer array gain
Output: Return the highest altitude reached
This problem belongs to the 1D Prefix Sum category.
Starting from i = 0, we iterate through gain, continuously accumulating the current altitude.
We use an ans (or highest) variable to record the maximum altitude seen during the traversal.
Note that the initial altitude of 0 is also included in the comparison.
Implementation
class Solution:
def largestAltitude(self, gain: List[int]) -> int:
# Initialize maximum altitude and current altitude to 0
maxAltitude = 0
currAltitude = 0
# Iterate over the gain array, calculating the current altitude and max altitude at each step
for g in gain:
# Current altitude is the cumulative sum of step height changes
currAltitude += g
# Update the maximum altitude
maxAltitude = max(maxAltitude, currAltitude)
# Return the maximum altitude
return maxAltitudevar largestAltitude = function(gain) {
let highest = 0;
let currHeight = 0;
for (let g of gain) {
currHeight += g;
highest = Math.max(highest, currHeight);
}
return highest;
};Complexity Analysis
- Time Complexity: O(n)
- Space Complexity: O(1)
Links
1732. Find the Highest Altitude (English)1732. 找到最高海拔 (Chinese)